// Step 1: Find the pivot for (i = n - 2; i >= 0; i--) if (str[i] < str[i + 1]) break;
int main() int t; scanf("%d", &t);
printf("%s\n", str);
void biggerIsGreater(char *str) int n = strlen(str); int i, j;
// Step 3: Swap pivot with that character swap(&str[i], &str[j]); bigger is greater hackerrank solution c
// Step 2: Find the smallest character on right of pivot that is greater than str[i] for (j = n - 1; j > i; j--) if (str[j] > str[i]) break;
if (i < 0) printf("no answer\n"); return; // Step 1: Find the pivot for (i
Here’s a structured report on solving the HackerRank problem using C . Problem Statement Given a word (string of lowercase English letters), find the lexicographically smallest greater permutation of its characters. If no such permutation exists (i.e., the string is already the largest possible), return "no answer" .
void reverse(char *str, int start, int end) while (start < end) swap(&str[start], &str[end]); start++; end--; void reverse(char *str, int start, int end) while
while (t--) char str[101]; scanf("%s", str); biggerIsGreater(str);
// Step 4: Reverse the suffix after pivot reverse(str, i + 1, n - 1);