t(20)+13=33→7(g) t(20)+13=7(g) b(2)+13=15(o) y(25)+13=38→12(l) q(17)+13=30→4(d) → ggold ? Interesting: guzly ggold — not quite.
t(20) +11 = 31 → 5 (e) h(8) +11 = 19 (s) m(13) +11 = 24 (x) y(25) +11 = 36 → 10 (j) l(12) +11 = 23 (w) → esxjw — no. (ROT-5 backward = ROT-21) thmyl ttbyq Cee synmana llayfwn
t(20) -5 = 15 (p) h(8) -5 = 3 (c) m(13) -5 = 8 (h) y(25) -5 = 20 (t) l(12) -5 = 7 (g) → pchtg ? No. thmyl ttbyq Cee synmana llayfwn