Turbo Physics Grade 12 Pdf < Top 20 Top >

Density ratio vs. ambient: 1.89/1.18 = 1.60 → 60% more air.

He learned is the time to reach the boost threshold. It’s governed by the moment of inertia of the rotating assembly and the exhaust enthalpy flow .

That diagram became the cover of a new PDF guide: Turbo Physics for Grade 12 . If you want, I can convert this story into a clean, printable PDF layout with diagrams (described in text) and a formula summary page. Just let me know, and I’ll generate the PDF-ready content.

New density at 1.7 atm, 45°C (318 K): ρ = (1.7×101325)/(287×318) ≈ 172252/91266 ≈ 1.89 kg/m³ turbo physics grade 12 pdf

“More air means more fuel can be burned,” Kael said. “That’s the power gain.” But 135°C air caused engine knock. Dr. Vane handed him an intercooler—an air-to-air radiator. After the intercooler, temperature dropped to 45°C while pressure only dropped to 1.7 atm.

At 1.8 atm and 135°C (408 K): ρ = (1.8 × 101325 Pa) / (287 J/kg·K × 408 K) ρ ≈ 182385 / 117096 ≈ 1.56 kg/m³

Using angular dynamics: τ = I × α, where τ = torque from turbine, I = rotational inertia, α = angular acceleration. Density ratio vs

For air, γ = 1.4, so (0.4/1.4) = 0.286.

Power_compressor = ṁ_air × cp_air × (T_out – T_in) / η_mech

Without turbo, ambient air density was 1.18 kg/m³. Density ratio = 1.56/1.18 = 1.32 → 32% more air molecules. It’s governed by the moment of inertia of

“Cooling after compression is like cheating physics,” Kael grinned. “You increase density without losing the work already put in.” The turbo didn’t work instantly. At low RPM, exhaust flow was weak. Kael plotted mass flow rate vs. pressure ratio on a compressor map. The surge line showed where airflow reversed—flutter. The choke line where flow stalled.

T₂ = T₁ × (P₂/P₁)^((γ-1)/γ)