[ \varepsilon(x) = \sum_{m=-\infty}^{\infty} \varepsilon_m , e^{i m K x}, \quad K = \frac{2\pi}{a} ]
Even with jumps, the Fourier coefficients (\varepsilon_m) decay as (1/m) (for a step change). Meanwhile, the electric field or pressure wave is assumed to follow Bloch’s theorem:
Let’s explore how engineers and physicists use Fourier series to model and solve real-world discontinuous periodic systems. Consider a perfect square wave—a signal that jumps instantly between +1 and -1. This is the poster child for discontinuity. Its Fourier series is: This is the poster child for discontinuity
[ f(x) = \frac{4}{\pi} \sum_{n=1,3,5,\ldots} \frac{\sin(nx)}{n} ]
[ E(x) = e^{i k x} \sum_{n=-\infty}^{\infty} E_n , e^{i n K x} ] Embrace the Fourier series—just remember to keep enough
The surprising answer is that when analyzing physical structures with abrupt changes—think square waves, step-index optical fibers, digital signals, or phononic crystals.
Don’t fear the jump. Embrace the Fourier series—just remember to keep enough harmonics to capture the edge. step-index optical fibers
If you’ve ever studied Fourier series, you likely remember the core idea: any periodic function can be broken down into a sum of simple sine and cosine waves. But then came the catch—the series often struggles with discontinuities , producing that infamous 9% overshoot known as the Gibbs phenomenon. So why would anyone want to use Fourier series on discontinuous problems?